### 2+2=5 Proved

November 8, 2017Prove That, 2+2=5

We Know, 2+2=4

After going through this for almost 30 minutes, I was not able to figure out the mistake in this. What is wrong in this?

$WeKnow,2+2=4\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}or,2+2=4\phantom{\rule{0ex}{0ex}}=4-\frac{9}{2}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$$=\sqrt{(4-\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$

$=\sqrt{16-2.4.\frac{9}{2}+(\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=\sqrt{16-36+(\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=\sqrt{-20+(\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=\sqrt{25-45+(\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=\sqrt{(5{)}^{2}-2.5.\frac{9}{2}+(\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=\sqrt{(5-\frac{9}{2}{)}^{2}}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}=5-\frac{9}{2}+\frac{9}{2}\phantom{\rule{0ex}{0ex}}\left(\mathbf{P}\mathbf{r}\mathbf{o}\mathbf{v}\mathbf{e}\mathbf{d}\right)$

After going through this for almost 30 minutes, I was not able to figure out the mistake in this. What is wrong in this?

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